public E remove(int index){ // index范围检查 rangeCheck(index);
modCount++; // 获取index索引对应的元素 E oldValue = elementData(index);
// 计算元素位置是否移动了,并调整元素位置 int numMoved = size - index - 1; if (numMoved > 0) System.arraycopy(elementData, index+1, elementData, index, numMoved); // 将最后一个元素设置为null elementData[--size] = null; // clear to let GC do its work
Object[] a = c.toArray(); int numNew = a.length; if (numNew == 0) returnfalse;
// 找出当前节点,与前一个节点 Node<E> pred, succ; if (index == size) { succ = null; pred = last; } else { succ = node(index); pred = succ.prev; }
// 追加节点 for (Object o : a) { E e = (E) o; Node<E> newNode = new Node<>(pred, e, null); if (pred == null) first = newNode; else pred.next = newNode; pred = newNode; }
解释一下public boolean addAll(int index, Collection<? extends E> c) {…}
第一种情况:
当index == size大小时,从尾部添加。
第二种情况:
当index < size大小时, 从中间插入。
我们依旧看看add,remove,set
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publicbooleanadd(E e){ linkLast(e); returntrue; }
// 在最后一个节点上追加节点 voidlinkLast(E e){ final Node<E> l = last; final Node<E> newNode = new Node<>(l, e, null); last = newNode; if (l == null) first = newNode; else l.next = newNode; size++; modCount++; }
publicbooleanremove(Object o){ if (o == null) { for (Node<E> x = first; x != null; x = x.next) { if (x.item == null) { unlink(x); returntrue; } } } else { for (Node<E> x = first; x != null; x = x.next) { if (o.equals(x.item)) { unlink(x); returntrue; } } } returnfalse; }
E unlink(Node<E> x){ // assert x != null; final E element = x.item; final Node<E> next = x.next; final Node<E> prev = x.prev;
if (prev == null) { first = next; } else { prev.next = next; x.prev = null; }
if (next == null) { last = prev; } else { next.prev = prev; x.next = null; }
if (index < (size >> 1)) { Node<E> x = first; for (int i = 0; i < index; i++) x = x.next; return x; } else { Node<E> x = last; for (int i = size - 1; i > index; i--) x = x.prev; return x; } }